3x^2-8=2x^2+8

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Solution for 3x^2-8=2x^2+8 equation:


Simplifying
3x2 + -8 = 2x2 + 8

Reorder the terms:
-8 + 3x2 = 2x2 + 8

Reorder the terms:
-8 + 3x2 = 8 + 2x2

Solving
-8 + 3x2 = 8 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
-8 + 3x2 + -2x2 = 8 + 2x2 + -2x2

Combine like terms: 3x2 + -2x2 = 1x2
-8 + 1x2 = 8 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-8 + 1x2 = 8 + 0
-8 + 1x2 = 8

Add '8' to each side of the equation.
-8 + 8 + 1x2 = 8 + 8

Combine like terms: -8 + 8 = 0
0 + 1x2 = 8 + 8
1x2 = 8 + 8

Combine like terms: 8 + 8 = 16
1x2 = 16

Divide each side by '1'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}

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